~~~~~~ 3rd Lecture - Networking IP Subnetting ~~~~~~~~

[k2s]

[quote author=ROBO link=topic=234570.msg2924136#msg2924136 date=1315519808]
e thread naku chala imp ippudu chaduvu ta padukoni  s%H# s%H#
[/quote] sFun_duh sFun_duh sFun_duh

[krldr871]

question ippudu ardam ayindi..network address and number of hosts aa

172.16.16 .0 idi network address
4094 hosts

[k2s]

[quote author=John Galt link=topic=234570.msg2924088#msg2924088 date=1315519409]
16 subnets 2^12 - 2 hosts ankunta
[/quote]

DeviceB: 172.16.28 .15/20

ki number of subnets, hosts, broadcast IP , etc details with explantion needed

[krldr871]

172.16.31.255 is the broadcast address..
subnet address is 20 bits, so left nunchi 1st 20 bits teeskunte network address vastadi..
ip address & ~subnetmask teeskunte broadcast address vastadi..

[k2s]

[quote author=John Galt link=topic=234570.msg2924169#msg2924169 date=1315520042]
question ippudu ardam ayindi..network address and number of hosts aa

172.16.16 .0 idi network address
4094 hosts
[/quote]qochen vesa kinda chudu

[krldr871]

[quote author=k2s link=topic=234570.msg2924200#msg2924200 date=1315520278]
qochen vesa kinda chudu
[/quote]
&D_@@ &D_@@ &D_@@
[quote author=John Galt link=topic=234570.msg2924198#msg2924198 date=1315520268]
172.16.31.255 is the broadcast address..
subnet address is 20 bits, so left nunchi 1st 20 bits teeskunte network address vastadi..
ip address & ~subnetmask teeskunte broadcast address vastadi..
[/quote]

[k2s]

[quote author=k2s link=topic=234570.msg2924172#msg2924172 date=1315520054]
DeviceB: 172.16.28 .15/20

ki number of subnets, hosts, broadcast IP , etc details with explantion needed
[/quote]Ok the answer is :


Determining the Subnet for DeviceB:

172.16.28.15  -  10101100.00010000.00011100.00001111
255.255.240.0 -  11111111.11111111.11110000.00000000
                            --------------------------| sub|------------
subnet    =          10101100.00010000.[color=red]0001[/color][color=green]0000.00000000[/color] = 172.16.16.0
Host range =      10101100.00010000.[color=red]0001[/color][color=green]0000.00000001[/color] = 172.16.16.1 to
                            10101100.00010000.[color=red]0001[/color][color=green]1111.11111110[/color] = 172.16.31.254

BC          =          10101100.00010000.[color=red]0001[/color][color=green]1111.11111111[/color] = 172.16.31.255

[krldr871]

[quote author=k2s link=topic=234570.msg2924229#msg2924229 date=1315520539]
Ok the answer is :


Determining the Subnet for DeviceB:

172.16.28.15  -  10101100.00010000.00011100.00001111
255.255.240.0 -  11111111.11111111.11110000.00000000
                            --------------------------| sub|------------
subnet    =          10101100.00010000.[color=red]0001[/color][color=green]0000.00000000[/color] = 172.16.16.0
Host range =      10101100.00010000.[color=red]0001[/color][color=green]0000.00000001[/color] = 172.16.16.1 to
                            10101100.00010000.[color=red]0001[/color][color=green]1111.11111110[/color] = 172.16.31.254

BC          =          10101100.00010000.[color=red]0001[/color][color=green]1111.11111111[/color] = 172.16.31.255
[/quote]

na answer lu count cheyyava  *7*^ *7*^ *7*^ *7*^

[k2s]

[quote author=John Galt link=topic=234570.msg2924218#msg2924218 date=1315520476]
&D_@@ &D_@@ &D_@@
[/quote]

ila ivvali answer

*7*^

[quote author=k2s link=topic=234570.msg2924229#msg2924229 date=1315520539]
Ok the answer is :


Determining the Subnet for DeviceB:

172.16.28.15  -  10101100.00010000.00011100.00001111
255.255.240.0 -  11111111.11111111.11110000.00000000
                            --------------------------| sub|------------
subnet    =          10101100.00010000.[color=red]0001[/color][color=green]0000.00000000[/color] = 172.16.16.0
Host range =      10101100.00010000.[color=red]0001[/color][color=green]0000.00000001[/color] = 172.16.16.1 to
                            10101100.00010000.[color=red]0001[/color][color=green]1111.11111110[/color] = 172.16.31.254

BC          =          10101100.00010000.[color=red]0001[/color][color=green]1111.11111111[/color] = 172.16.31.255
[/quote]

[k2s]

[quote author=John Galt link=topic=234570.msg2924237#msg2924237 date=1315520583]
na answer lu count cheyyava  *7*^ *7*^ *7*^ *7*^
[/quote]

i want full explanation......  *7*^

[robo]

[quote author=k2s link=topic=234570.msg2924229#msg2924229 date=1315520539]
Ok the answer is :


Determining the Subnet for DeviceB:

172.16.28.15  -  10101100.00010000.00011100.00001111
255.255.240.0 -  11111111.11111111.11110000.00000000
                            --------------------------| sub|------------
subnet    =          10101100.00010000.[color=red]0001[/color][color=green]0000.00000000[/color] = 172.16.16.0
Host range =      10101100.00010000.[color=red]0001[/color][color=green]0000.00000001[/color] = 172.16.16.1 to
                            10101100.00010000.[color=red]0001[/color][color=green]1111.11111110[/color] = 172.16.31.254

BC          =          10101100.00010000.[color=red]0001[/color][color=green]1111.11111111[/color] = 172.16.31.255
[/quote] #4H# #4H# ippudu artaham ayindhochhhhhhhh  J@#D J@#D

[robo]

[quote author=k2s link=topic=234570.msg2924242#msg2924242 date=1315520620]
i want full explanation......  *7*^
[/quote]question kuda fullga explain cheyali teacherrr  @3$%

[krldr871]

[quote author=k2s link=topic=234570.msg2924242#msg2924242 date=1315520620]
i want full explanation......  *7*^
[/quote]
bit level lo anni bits rayalante baaga time pattuddi baa..or lu and le kada..chusi cheseyachu ani  cry@fl cry@fl

[k2s]

1 more example:

[img]http://www.cisco.com/image/gif/paws/13788/3c.gif[/img]
Given the Class C network of 204.15.5.0/24, subnet the network in order to create the network in Figure  with the host requirements shown.

any one who can solve it for me..... please give full explanation...

[k2s]

[quote author=ROBO link=topic=234570.msg2924247#msg2924247 date=1315520681]
#4H# #4H# ippudu artaham ayindhochhhhhhhh  J@#D J@#D
[/quote] H&*()